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Light of wavelength 6000 A0 is incident normally on a slit of width 24×105 cm. Find out the angular position of second minimum from central maximum

a
530
b
370
c
300
d
600

detailed solution

Correct option is C

For 2nd minimum,  asinθ=2λ   put  λ=6×10−7m,  a=24×10−5×10−2m  ⇒sinθ=2λa=2×6×10−724×10−7=12 ∴θ=300

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