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Light of wavelength 6328 A0 is incident normally on a slit of width 0.2 mm. Calculate the angular width of central maximum on a screen distance 9 m.

a
0.56 rad
b
0.46 rad
c
0.36 rad
d
0.26 rad

detailed solution

Correct option is C

Given λ=6.328×10−7m, a=0.2×10−3m  Angular Fringe Width, w0=2λa=2×6.328×10−72×10−4radian  ⇒ w0 =6.328×10−3×1803.14=0.36 radian

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