Light of wavelength λ is incident on a slit of width d. The resulting diffraction pattern is observed on a screen at a distance D. The linear width of the principal maximum is then equal to the width of the slit if D equals

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d/λ

2λ/d

d2/2λ

2λ2/d

answer is C.

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Detailed Solution

Linear width of principal maximum=2λd×DAccording to the given problemd=2λd×D or D=d22λ

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