Light of wavelength λ is incident on a slit of width d. The resulting diffraction pattern is observed on a screen at a distance D. The linear width of the principal maximum is then equal to the width of the slit if D equals
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a
d/λ
b
2λ/d
c
d2/2λ
d
2λ2/d
answer is C.
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Detailed Solution
Linear width of principal maximum=2λd×DAccording to the given problemd=2λd×D or D=d22λ