Light of wavelength 400 nm is incident continuously on a Cesium ball (work function 1.9 eV). Find the maximum potential (in V) to which the ball will be charged.

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answer is 1.2.

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Detailed Solution

We use eVS=hcλ−ϕ=1240(nm)eV400(nm)−1.9eV⇒eVS=1.2eV⇒VS=1.2VThus the cesium ball can be charged to a maximum potential of 1.2 V.

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