First slide

Diffraction

Question

Light of wavelength 589.3 nm is incident normally on the slit of width 0.1 mm. What will be the angular width of the central diffraction maximum at a distance of 1 m from the slit?

Easy

A

0.68⁰
B

1.02⁰
C

0.34⁰
D

None of these

Solution

Angular width of central maxima $= \frac{2 λ}{d}$
$= \frac{2 \times 589 .3 \times 10^{- 9}}{0 .1 \times 10^{- 3}} rad = 0 .0117 \times \frac{180}{π} = 0 {.68}^{\circ}$

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