Light of wavelength 0.6 pm from a sodium lamp falls on a photocell and causes the emission of photoelectrons for which the stopping potential is 0.5 V. With light of wavelength 0.4 μm from a mercury vapor lamp, the stopping potential is 1.5 V. Then, the work function [in electron volts] of the photocell surface is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
0.75 eV
b
1.5 eV
c
3 eV
d
2.5 eV
answer is B.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
E−W0=12mv2=eVs or hcλ−W0=eVs Hence, hc0.6×10−6−W0=e(0.5) ........(i) and hc0.4×10−6−W0=e(1.5) ........(ii) Solving, we get W0=1.5eV