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Light of wavelength λ strikes a photo electric surface and electrons are ejected with maximum kinetic energy K. If K is to be increased to twice its original value, the wavelength must be changed to λ'. If λ=6200 Ao and λ'=5000 Ao, Then value of k is

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a

1.26 eV

b

0.86 eV

c

0.48 eV

d

1.62 eV

answer is C.

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Detailed Solution

(3)hcλ=ϕ+k....1 and hcλ'=ϕ+2k....22−1, k= hcλ'−hcλ= 124005000−124006200Ao=0.48 eV

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