First slide

Young's double slit Experiment

Question

Light of wavelength 5.0 x 10^-7 m falls on a pair of narrow slits separated by a distance (2d). The interference pattern on a screen placed 2.0 m away shows that there is darkness at the position exactly opposite to each slit. The separation between the slits

Moderate

A

0.5 mm
B

1.0 mm
C

2.0 mm
D

$5 \times 10^{- 7}$ mm

Solution

we know that $β = \frac{λD}{2 d}$
Here, tho distance between two dark fringes is equal to the separation between the slits i.e $β$ =2d
$(2 d) = \frac{λD}{(2 d)} or (2 d)^{2} = λD or (2 d) = \sqrt{(λD)} so (2 d) = {[5 \cdot 0 \times 10^{- 7} \times 2 \cdot 0]}^{1 / 2} = 10^{- 3} m = 1 \cdot 0 mm$

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