Light of wavelength $$5.0$$ x $$10-7$$ m falls on a pair of narrow slits separated by a distance (2d). The interference pattern on a screen placed $$2.0$$ m away shows that there is darkness at the position exactly opposite to each slit. The separation between the slits

Question

Light of wavelength $$5.0$$ x $$10-7$$ m  falls on a pair of narrow slits separated by a distance (2d). The interference pattern on a screen placed $$2.0$$ m away shows that there is darkness at the position exactly opposite to each  slit. The separation between the slits

Infinity Learn · Accepted Answer

we know that β$$=$$λ$$D2dHere$$, tho distance between two dark fringes is equal to the separation between the slits i.e β $$=2d(2d)=$$λ$$D(2d)$$  or  (2d)2=$$λD or $$(2d)=($$λ$$D) so $$(2d)=5$$⋅$$0$$×$$10$$−$$7$$×$$2$$⋅$$01/2=10$$−$$3m=1$$⋅$$0mm$$

Light of wavelength 5.0 x 10^-7 m falls on a pair of narrow slits separated by a distance (2d). The interference pattern on a screen placed 2.0 m away shows that there is darkness at the position exactly opposite to each slit. The separation between the slits

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Light of wavelength 5.0 x 10-7 m falls on a pair of narrow slits separated by a distance (2d). The interference pattern on a screen placed 2.0 m away shows that there is darkness at the position exactly opposite to each slit. The separation between the slits

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Ready to Test Your Skills?

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Light of wavelength 5.0 x 10^-7 m falls on a pair of narrow slits separated by a distance (2d). The interference pattern on a screen placed 2.0 m away shows that there is darkness at the position exactly opposite to each slit. The separation between the slits