Questions
Lights of two different frequencies, whose photons have energies 1eV and 2.5eV respectively, successively illuminate a metal whose work function is 0.5eV. The ratio of the maximum speeds of the emitted electrons will be
detailed solution
Correct option is C
Einstein equation KEmax=E− Work function; ⇒12mv2=E−W∴12mV12max12 mV22max=1−0.52.5−0.5=14 ⇒ V1maxV2max=12Talk to our academic expert!
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Figure shows the stopping potential (V)versus frequency (v) graph for photoelectric effect in a metal. From the graph, The Planck's constant (h) is . The value of y is
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