Questions
The limit of Balmer series is 8646 The wavelength of the first member of this series will be
a
6563Å
b
3646Å
c
7200Å
d
1000Å
detailed solution
Correct option is A
1λ=R1n12−1n22 For the limit of Balmer series, we have 1λlim=R122−1∞=R4 and 1λfirst =R122−132=5R36 λfirst =λlim365×4=3646×95=6563ÅTalk to our academic expert!
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