In the line spectra of hydrogen atom, difference between the largest and the shortest wavelenths of the Lyman series is 304  $\stackrel{0}{A}$. The corresponding difference for the Paschan series in $\stackrel{0}{A}$  is : ___________ .

Largest wavelength  $\Rightarrow$ minimum energy and vice-versa.
Lyman
$\begin{array}{l}\frac{1}{{\lambda }_{\max }}=\mathrm{R}\left(\frac{1}{1^2}-\frac{1}{2^2}\right)\Rightarrow {\lambda }_{\max }=\frac{4}{3\mathrm{R}}\\ \frac{1}{{\lambda }_{\min }}=\mathrm{R}\left(\frac{1}{1^2}-\frac{1}{{\infty }^2}\right)\Rightarrow {\lambda }_{\min }=\frac{1}{\mathrm{R}}\\ {\lambda }_{\max }-{\lambda }_{\min }=\frac{1}{3\mathrm{R}}=304\stackrel{0}{A}\end{array}$

Paschen

$\begin{array}{l}\frac{1}{{\lambda }_{\max }}=\mathrm{R}\left(\frac{1}{3^2}-\frac{1}{4^2}\right)\Rightarrow {\lambda }_{\max }=\frac{16\times 9}{7\mathrm{R}}\\ \frac{1}{{\lambda }_{\min }}=\mathrm{R}\left(\frac{1}{3^2}-\frac{1}{{\infty }^2}\right)\Rightarrow {\lambda }_{\min }=\frac{9}{\mathrm{R}}\\ {\lambda }_{\max }-{\lambda }_{\min }=\frac{81}{7\mathrm{R}}=\frac{81}{7}\times 3\times 304 \stackrel{0}{A}\\ =10553.14 \stackrel{0}{A}\end{array}$