In the line spectra of hydrogen atom, difference between the largest and the shortest wavelenths of the Lyman series is 304  A0. The corresponding difference for the Paschan series in A0  is : ___________ .

Largest wavelength  ⇒ minimum energy and vice-versa.Lyman1λmax=R112-122⇒λmax=43R1λmin=R112-1∞2⇒λmin=1Rλmax-λmin=13R=304A0Paschen1λmax=R132-142⇒λmax=16×97R1λmin=R132-1∞2⇒λmin=9Rλmax-λmin=817R=817×3×304 A0=10553.14 A0