Download the app

Questions  

A linear harmonic oscillator of force constant 2×106N/m times and amplitude 0.01 m has a total mechanical energy of 160 joules. Its

a
Maximum potential energy is 100 J
b
Maximum K.E. is 160 J
c
Maximum P.E. is 160 J
d
Minimum P.E. is zero

detailed solution

Correct option is C

As, we know total mechanical energy = maximum potential energy ∴AT  Q, T.E=160J⇒Max.P.E.=160J

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

When the displacement is half the amplitude, the ratio of potential energy to the total energy is


phone icon
whats app icon