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Questions  

A linear harmonic oscillator of force constant 2×106 Nm-1and amplitude 0.01 m has a total mechanical energy 160 J. Among the following statements, which are correct?

i. Maximum PE is 100 J
ii. Maximum KE is 100 J
iii. Maximum PE is 160 J
iv. Minimum PE is zero

a
Both (i) and (iv)
b
Both (ii) and (iii)
c
Both (i) and (ii)
d
Both (ii) and (iv)

detailed solution

Correct option is B

Total mechanical energy is ET = 160 J ∴  Umax = 160 JAt extreme position KE is zero. Work done by spring force from extreme position to mean position isW = 12kA2∴  Kmax = W = 12(2×106)(0.01)2 = 100 J∴  Umin= 160-100 = 60 J

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