A linearly polarized electromagnetic wave given as E→=E0cos(kz−wt)i^ is incident normally on a perfectly reflecting infinite wall at z=a. Assuming that the material of the wall is optically inactive, the reflected wave will be given as
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a
Er¯=−E0i^ cos (kz−wt)
b
Er¯=E0i^ cos (kz+wt)
c
Er¯=−E0i^ cos (kz+wt)
d
Er¯=E0i^ cos (kz−wt)
answer is B.
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Detailed Solution
When a wave is reflected from denser medium the reflected wave is without change in type of wave but with a change in phase by 1800 or π radian. Therefore, additional phase of π in the incident wave is introduced. Also, the direction is reversed hence, for the reflected wave we will replace z by−z (in the phase) and i^ by −i^ . The incident electromagnetic wave is,E→=Eocos(kz−wt)i^ The reflected electromagnetic wave isEr→=E0cos[k(−z)−wt+π](-i^) = −E0cos[−(kz+wt)+π]i^ =E0cos[(kz+wt)] i^ [cos(−θ+π)=-cos(θ)]