A linearly polarized electromagnetic wave given as $E = E_{0} \hat{i} \cos (k z - ω t)$ is incident normally on a perfectly reflacting wall $z = a$ . Assuming that the material of the optically inactive, the reflected wave will be given as
View solution

Question

A linearly polarized electromagnetic wave given as $E = E_{0} \hat{i} \cos (k z - ω t)$ is incident normally on a perfectly reflacting wall $z = a$ . Assuming that the material of the optically inactive, the reflected wave will be given as

View solution

Infinity Learn · Accepted Answer

When a wave is reflected  from denser medium the reflected wave is without change in type of wave but with a change in phase by $$1800$$ or π radian. Therefore, additional phase of π in the incident wave is introduced. Also, the direction is reversed hence,  for the reflected wave we will replace   z by−z (in$$ the $$phase) and $$i^$$ by −$$i^$$ . The incident electromagnetic wave is,E→$$=Eocos(kz$$−$$wt)i^$$ The reflected electromagnetic wave isEr→$$=E0cos$$[$$k($$−$$z)$$−$$wt+$$π]$$(-i^)$$  $$=$$ −$$E0cos$$[−(kz+wt)+$$π]$$i^$$ $$=E0cos$$[$$(kz+wt)] $$i^$$                 [$$cos$$$$($$−θ$$+$$π$$)=-$$$$cos$$$$($$θ$$)$$]

A linearly polarized electromagnetic wave given as $\vec{E} = E_{0} \cos (k z - w t) \hat{i}$ is incident normally on a perfectly reflecting infinite wall at z=a. Assuming that the material of the wall is optically inactive, the reflected wave will be given as

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

A linearly polarized electromagnetic wave given as E→=E0cos(kz−wt)i^ is incident normally on a perfectly reflecting infinite wall at z=a. Assuming that the material of the wall is optically inactive, the reflected wave will be given as

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

A linearly polarized electromagnetic wave given as $\vec{E} = E_{0} \cos (k z - w t) \hat{i}$ is incident normally on a perfectly reflecting infinite wall at z=a. Assuming that the material of the wall is optically inactive, the reflected wave will be given as