A linearly polarized electromagnetic wave given as $\vec{E} = E_{0} \cos (k z - w t) \hat{i}$ is incident normally on a perfectly reflecting infinite wall at z=a. Assuming that the material of the wall is optically inactive, the reflected wave will be given as
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Question

A linearly polarized electromagnetic wave given as $\vec{E} = E_{0} \cos (k z - w t) \hat{i}$ is incident normally on a perfectly reflecting infinite wall at z=a. Assuming that the material of the wall is optically inactive, the reflected wave will be given as

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Infinity Learn · Accepted Answer

When a wave is reflected from a denser medium (or) perfectly reflecting wll made with optically inactive material then the type of wave doesn’t change but only its phase changes by $$1800$$ or π radianGiven here the incident electromagnetic wave is  E¯$$=E0i^coskz$$−ωtThis wave is incident normally on a perfectly reflecting infinite wall at $$z=a$$ . Here the reflected wave in the direction of travelling of wave will be reversed and additional phase of π in the incident waveEr¯$$=E0i^cosk$$−z−ω$$t+$$π Er¯$$=$$−$$E0i^$$$$cos$$−$$kz+$$ω$$t+$$π Er¯$$=E0i^$$$$cos$$−$$kz+$$ωtEr¯$$=E0i^coskz+$$ωt

A linearly polarized electromagnetic wave given as $E = E_{0} \hat{i} \cos (k z - ω t)$ is incident normally on a perfectly reflacting wall $z = a$ . Assuming that the material of the optically inactive, the reflected wave will be given as

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A linearly polarized electromagnetic wave given as E=E0i^coskz−ωt is incident normally on a perfectly reflacting wall z=a. Assuming that the material of the optically inactive, the reflected wave will be given as

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A linearly polarized electromagnetic wave given as $E = E_{0} \hat{i} \cos (k z - ω t)$ is incident normally on a perfectly reflacting wall $z = a$ . Assuming that the material of the optically inactive, the reflected wave will be given as