A linearly polarized electromagnetic wave given as $\overrightarrow{E}=E_o\cos (kz-wt) \hat{i}$ is incident normally on a perfectly reflecting infinite wall at $z=a$ . Assuming that the material of the wall is optically inactive,  the reflected wave will be given as

detailed solution

Correct option is B

When a wave is reflected from a denser medium, the reflected wave is without change in type of wave but with a change in phase by 1800 or π radian. Therefore,  additional phase of π is introduced in the incident wave . For the reflected wave direction is reversed means reflected wave travels in -i^ . As a result in the phase +kz is replaced by -kz . The incident electromagnetic wave isE→=Eocos(kz−wt)i^ The reflected em wave will be ,Er→=Eo(−i^)cos[-k(z)-wt+π]  =−Eoi^cos[−(kz+wt)+π]  =Eoi^cos[−(kz+wt)][cos(θ+π)=−cosθ] =Eoi^cos(kz+wt) [cos(−θ)=cosθ]