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A lineman of mass 60 kg is holding a vertical pole. The coefficient of static friction between his hands and the pole is 0.5. If he is able to climb up the pole, what is the minimum force with which he should press the pole with his hands? (g = 10 m/s2)

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a
1200 N
b
600 N
c
300 N
d
150 N

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detailed solution

Correct option is A

F=mg=μN=mg⇒N=mgμ=60(10)0.5=1200 newton


Similar Questions

A person just holds a block weighing 2kg between his hands & just keeps it from falling down by pressing it with his hands. If the force exerted by each hand horizontally is 50N, the coefficient of friction between the hand & the block is g=10ms2
 


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