First slide

Friction on horizontal surface

Question

A lineman of mass 60 kg is holding a vertical pole. The coefficient of static friction between his hands and the pole is 0.5. If he is able to climb up the pole, what is the minimum force with which he should press the pole with his hands? (g = 10 m/s²)

Easy

A

1200 N
B

600 N
C

300 N
D

150 N

Solution

$\begin{array}{l} F = mg = μN = mg \\ \Rightarrow N = \frac{mg}{μ} = \frac{60 (10)}{0 .5} = 1200 newton \end{array}$

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