The lines of force of the electric field of a positive charge (+q) and a negative charge (-q) are shown in figs. (A) and (B) below. Then the wrong option is
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a
the work done in moving a small positive charge (+q0) from Q to P will be positive
b
the work done in moving a small negative charge (-qo) from B to A will be positive
c
in going from Q to P the kinetic energy of a small negative charge (-qo) increases
d
in going from B to A, the kinetic energy of a small negative charge (- qo) decreases.
answer is A.
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Detailed Solution
In fig.(a);U=−q0VQ−VP ∵Wq0=q4πϵ0rQ−q4πϵ0rP∵VQVA∴PE. of-qo charge increases by some amount. Then K.E. decreases by same amount.