First slide

Thermal expansion

Question

A liquid column of height 80cm at 0°C balances the same liquid of height 80.4cm at 100°C. γ_R is

Easy

A

4 x 10^–5/°C
B

3 x 10^–5/°C
C

5 x 10^–5/°C
D

6 x 10^–5/°C

Solution

Given that h₁ = 80cm, h₂ = 80.4cm; t₁ = 0⁰C, t₂ = 100⁰C
We have $\large \gamma_R=\frac {h_2-h_1}{h_1t_2-h_2t_1}$
$\large =\frac {80.4-80}{(80)(100)-0}=5\times 10^{-5}/^0C$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App