First slide

Radiation

Question

A liquid cools from 50⁰C to 45⁰C in 5 min and from 45⁰C to 41.5⁰C in the next 5 min. The temperature of the surrounding is

Moderate

A

27⁰C
B

40.3⁰C
C

23.3⁰C
D

33.3⁰C

Solution

Applying $\frac{θ_{1} - θ_{2}}{t} = α (\frac{θ_{1} + θ_{2}}{2} - θ_{0}), we get$
$(where, α is constant)$
$\frac{50 - 45}{5} = α (\frac{50 + 45}{2} - θ_{0})$ …(i)
and $\frac{45 - 41.5}{5} = α (\frac{45 + 41.5}{2} - θ_{0})$ …(ii)
Solving these two equations, we get
$θ_{0}$ = temperature of surrounding = 33.3⁰C.

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App