Questions
A liquid of density contained in a vertical U tube filled to a height h on each limb. It executes simple harmonic motion in its limbs when a small disturbance is given. Then the time period of its oscillation is
detailed solution
Correct option is A
The restoring force responsible for oscillation is the weight of the liquid displaced. Hence using the condition for simple harmonic motion we can say that a=−ω2y . Here a=Fm . If the mass per unit length is μ, then F=μ(2y)g and m=μ(2h). Simplifying we get a=μ(2y)gμ(2h)=ygh Comparing this with a=−ω2y, we get ω2=gh.where ω=2πT. Hence the time period of oscillation is T=2πhgTalk to our academic expert!
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A U tube of uniform bore of cross-sectional area A has been set up vertically with open ends facing up. Now m gm of a liquid of density d is poured into it. The column of liquid in this tube will oscillate with a period T such that
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