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A liquid of density  ρ contained in a vertical U tube filled to a height h on each limb.  It executes simple harmonic motion in its limbs when a small disturbance is given.  Then the time period of its oscillation is

a
T=2πhg
b
T=2π2hg
c
T=2πgh
d
T=2πg2h

detailed solution

Correct option is A

The restoring force responsible for oscillation is the weight of the liquid displaced.  Hence using the condition for simple harmonic motion we can say that  a=−ω2y .  Here a=Fm . If the mass per unit length is   μ, then F=μ(2y)g  and  m=μ(2h).  Simplifying  we get  a=μ(2y)gμ(2h)=ygh   Comparing this with a=−ω2y,  we get ω2=gh.where  ω=2πT. Hence the time period of oscillation is  T=2πhg

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