First slide

Surface tension and surface energy

Question

A liquid drop of diameter D breaks upto into 27 small drops of equal size. If the surface tension of the liquid is $σ$ , then change in surface energy is

Moderate

A

${πD}^{2} σ$
B

$2 {πD}^{2} σ$
C

$3 {πD}^{2} σ$
D

$4 {πD}^{2} σ$

Solution

$\begin{matrix} Work done = 4 {πR}^{2} T (n^{1 / 3} - 1) = 4 π {(\frac{D}{2})}^{2} σ (n^{1 / 3} - 1) \\ = {πD}^{2} σ (27^{1 / 3} - 1) = 2 {πD}^{2} σ \end{matrix}$

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