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A liquid enters a tube of variable cross section with a velocity 4m/sec through wider end leaves from the narrower end whose radius is half of the wider one. The velocity with which it leaves the tube is

a
12 m/sec
b
16 m/ sec
c
20 m/sec
d
10 m/ sec

detailed solution

Correct option is B

A1v1=A2v2⇒πr12v1=πr22v2⇒r2×4=(r2)2v2 ⇒r2×4=r24v2⇒v2=16m/sec

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