First slide

Surface tension and surface energy

Question

A liquid film is formed in a loop of area 0.05 m². Increase in its potential energy will be (T = 0.2 N/m)

Easy

A

$5 \times 10^{- 2} J$
B

$2 \times 10^{- 2} J$
C

$3 \times 10^{- 2} J$
D

None of these

Solution

Increment in Potential energy = $T \times Δ A$
$= 0.2 \times 2 \times 0.05 = 2 \times 10^{- 2} J$

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