A liquid is flowing in a horizontal uniform capillary tube under a constant pressure difference P. The value of pressure for which the rate of flow of the liquid is doubled when the radius and length both are doubled is
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a
P
b
3P4
c
P2
d
P4
answer is D.
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Detailed Solution
From V=Pπr48ηl⇒P=V8ηlπr4⇒P2P1=V2V1×l2l1×r1r24=2×2×124=14∣⇒P2=P14=P4