A liquid is flowing through a tube at the rate of 0.1 m3/sec . The tube is branched into two semicircular tubes of cross-sectional area A/3 and 2A/3 . The velocity of liquid at Q is: (The cross-section of the main tube =A=10−2m2 and vp=20 m/s )
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
5 m/s
b
30 m/s
c
35 m/s
d
None of these
answer is A.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Equation of continuity Rate =r=A3vP+(A−A3)vQ ∴ vP+2vQ=3rA =3×0.110−2=30 m/s As vP=20 m/s Hence, vQ=5 m/s