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A liquid is flowing through a tube at the rate of $0.1 m^{3} / \sec$ . The tube is branched into two semicircular tubes of cross-sectional area $A / 3$ and $2 A / 3$ . The velocity of liquid at $Q$ is: (The cross-section of the main tube $= A = 10^{- 2} m^{2}$ and $v_{p} = 20 m / s$ )

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5 m/s

30 m/s

35 m/s

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detailed solution

Correct option is A

Equation of continuity Rate =r=A3vP+(A−A3)vQ ∴ vP+2vQ=3rA =3×0.110−2=30 m/s As vP=20 m/s Hence, vQ=5 m/s

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A liquid is flowing through a tube at the rate of 0.1 m3/sec . The tube is branched into two semicircular tubes of cross-sectional area A/3 and 2A/3 . The velocity of liquid at Q is: (The cross-section of the main tube =A=10−2m2 and vp=20 m/s )

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

A liquid is flowing through a tube at the rate of $0.1 m^{3} / \sec$ . The tube is branched into two semicircular tubes of cross-sectional area $A / 3$ and $2 A / 3$ . The velocity of liquid at $Q$ is: (The cross-section of the main tube $= A = 10^{- 2} m^{2}$ and $v_{p} = 20 m / s$ )