A liquid flows through a horizontal tube. The velocities of the liquid in the two sections, which have areas of cross - section A₁ and A₂, are V₁ and V₂ respectively. The difference in the levels of the liquid in the two vertical tubes is h.

a) The volume of the liquid flowing through the tube in unit time is A₁V₁.
b) $\large V_2-V_1=\sqrt {2gh}$
c) $\large V_2^2-V_1^2= {2gh}$
d) The energy per unit mass of the liquid is the same in both sections of the tube.

Question

Infinity Learn · Accepted Answer

Discharge $$=$$ $$A1V1$$ $$=$$ $$A2V2$$. Applying Bernoulli's equation between larger and smaller sections, we can write, From (1) and (2), . According to Bernoulli's principle energy per unit volume or unit mass or unit weight of the an ideal blowing fluid at all points in the flow region remain the same.

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