First slide

Viscosity

Question

Liquid flows through two capillary tubes connected in series. Their lengths are L and 2L and radii r and 2r respectively. The pressure difference across the first and
second tube are in the ratio :

Moderate

A

8
B

2
C

4
D

1/8

Solution

${(\frac{dQ}{dt})}_{1} = {(\frac{dQ}{dt})}_{2}, i . e ., (\frac{{πP}_{1} r_{1}^{4}}{8 {ηL}_{1}}) = (\frac{{πP}_{2} r_{2}^{4}}{8 {ηL}_{2}})$

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