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A liquid is kept in a cylindrical vessel. When the vessel is rotated about its axis. The liquid rises at its sides. The radius of the vessel is 0.05 m and the speed of rotation is 2 revolutions per second. The difference in the heights of the liquid at the centre and at the sides of the vessel will be (take g = 10 ms-2 and π2=10 )

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By Expert Faculty of Sri Chaitanya
a
2 cm
b
4 cm
c
1 cm
d
8 cm

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detailed solution

Correct option is A

h=v22g=r2w22g=0.05×4π22×10=25×10-4×16×π22×10=200×10-4m=2 cm w=4π  rad/sec
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Similar Questions

A liquid is kept in a cylindrical vessel which is rotated along its axis. The liquid rises at the side. If the radius of the vessel is 5 cm and the speed of rotation is 4 rev/s, then the difference in the height of the liquid at the centre of the vessel and its sides is

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