A liquid is kept in a cylindrical vessel. When the vessel is rotated about its axis. The liquid rises at its sides. The radius of the vessel is 0.05 m and the speed of rotation is 2 revolutions per second. The difference in the heights of the liquid at the centre and at the sides of the vessel will be (take g = 10 ms-2 and π2=10 )

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2 cm

4 cm

1 cm

8 cm

answer is A.

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Detailed Solution

h=v22g=r2w22g=0.05×4π22×10=25×10-4×16×π22×10=200×10-4m=2 cm w=4π rad/sec

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