First slide

Fluid statics

Question

A liquid is kept in a cylindrical vessel which is rotated along its axis. The liquid rises at its sides. If the radius of the vessel is 0.05 m and the speed of rotation is 2 rps , the difference in the height of liquid at the centre of the vessel and its sides is

Moderate

A

0.001 m
B

0.002 m
C

0.01 m
D

0.02 m

Solution

$h = \frac{r^{2} ω^{2}}{2 g} = \frac{(0.05)^{2} (2 \times 2 π)^{2}}{2 \times g} = 0.02 m$

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