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Q.

A liquid of mass m and specific heat c is heated to a temperature T. Another liquid of mass (m/2) and specific heat 2c is heated to a temperature 2T. If these two liquids aremixed, the resulting temperature of the mixture is:

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a

(2/3)T

b

(8/5)T

c

(3/5)T

d

(3/2)T

answer is D.

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Detailed Solution

Heat lost = Heat gained⇒        mc(Tf-T)=m22c(2T-Tf) ⇒                        Tf=32T
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