Questions
A liquid of mass m and specific heat c is heated to a temperature T. Another liquid of mass (m/2) and specific heat 2c is heated to a temperature 2T. If these two liquids are
mixed, the resulting temperature of the mixture is:
detailed solution
Correct option is D
Heat lost = Heat gained⇒ mc(Tf-T)=m22c(2T-Tf) ⇒ Tf=32TTalk to our academic expert!
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