A liquid of mass m and specific heat c is heated to a temperature T. Another liquid of mass (m/2) and specific heat 2c is heated to a temperature 2T. If these two liquids aremixed, the resulting temperature of the mixture is:

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(2/3)T

(8/5)T

(3/5)T

(3/2)T

answer is D.

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Detailed Solution

Heat lost = Heat gained⇒ mc(Tf-T)=m22c(2T-Tf) ⇒ Tf=32T

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