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Questions  

A liquid of mass m and specific heat c is heated to a temperature T. Another liquid of mass (m/2) and specific heat 2c is heated to a temperature 2T. If these two liquids are
mixed, the resulting temperature of the mixture is:

a
(2/3)T
b
(8/5)T
c
(3/5)T
d
(3/2)T

detailed solution

Correct option is D

Heat lost = Heat gained⇒        mc(Tf-T)=m22c(2T-Tf) ⇒                        Tf=32T

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