A liquid of mass M and specific heat S is at temperature 2t. If another liquid of thermal capacity 1.5 times at a temperature of t/3 of same mass is added to it, the resultant temperature will be

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(4/3)t

t/2

2t/3

answer is B.

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Detailed Solution

t0=M1S1t1+M2S2t2M1S1+M2S2Given : M1 = M, S1 = S, t1 = 2tM2S2=32MS,t2=t3∴t0=2MSt+32×t3MSMS+32MS=t

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