A listener moves toward stationary source with constant speed and crosses him, then correct graph between apparent frequency (f') with time (t) is
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answer is A.
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Detailed Solution
velocities are taken along the line joining the source and listener when listener moves towards the source then apparent frequency is more than the actual frequency n'=v+v0vn and after crossing it moves away from the source apparent frequency decreases n'=v-v0vn