A $$2$$ litre glass flask contains some mercury. It is found that at all temperatures, the volume of air inside the flask, remains the same. The volume of mercury inside the flask is α for glass $$=$$ $$9$$ × $$10$$−$$6/0C$$, and for mercury $$=$$ $$1.8$$ × $$10$$−$$4/0C)$$

Question

A $$2$$ litre glass flask contains some mercury. It is found that at all temperatures, the volume of air inside the flask, remains the same. The volume of mercury inside the flask is  α   for  glass $$=$$ $$9$$ × $$10$$−$$6/0C$$, and for mercury $$=$$  $$1.8$$  ×  $$10$$−$$4/0C)$$

Infinity Learn · Accepted Answer

Since volume of air in the flask remains the same, the expansion in volume of vessel is exactly equal to the volume Expansion of mercury∴    ΔVV   $$=$$  ΔVm⇒    VV .  γv .  ΔT  $$=$$  Vm  .  γm .  ΔT⇒    Vm  $$=$$  Vv .  γvγm  $$=$$  Vm  × $$3$$αγm⇒    Vm  $$=$$  $$2000$$ ×  $$3$$ × $$9$$ ×$$10$$−$$61.8$$ × $$10$$−$$4$$  $$cc=$$ $$300cc$$

	Column - I		Column - II
a	$γ_{g} < γ_{R}$	p	liquid level rises continuously from beginning
b	$γ_{g} = γ_{R}$	q	liquid level falls continuously from beginning
c	$γ_{g} > γ_{R}$	r	liquid level remains same
d	$γ_{g} = 0$	s	liquid level first falls and then rises

A 2 litre glass flask contains some mercury. It is found that at all temperatures, the volume of air inside the flask, remains the same. The volume of mercury inside the flask is $(α for glass = 9 \times 10^{- 6} /^{0} C),$ and for mercury = $1 .8 \times 10^{- 4} /^{0} C)$

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A 2 litre glass flask contains some mercury. It is found that at all temperatures, the volume of air inside the flask, remains the same. The volume of mercury inside the flask is α for glass = 9 × 10−6/0C, and for mercury = 1.8 × 10−4/0C)

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A 2 litre glass flask contains some mercury. It is found that at all temperatures, the volume of air inside the flask, remains the same. The volume of mercury inside the flask is $(α for glass = 9 \times 10^{- 6} /^{0} C),$ and for mercury = $1 .8 \times 10^{- 4} /^{0} C)$