5.6 litre of the helium gas at STP is adiabatically compressed to 0.7 litre.Taking the initial temperature to be T1 , the work done in the process is :
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a
98RT1
b
32RT1
c
158RT1
d
92RT1
answer is A.
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Detailed Solution
TVγ-1=constant ⇒T2=5.60.723(T1)=4T1 Work done W=nR∆T1-γ=1/4R3T1-2-3=-98RT1