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Q.

A Lloyd’s mirror of length 5 cm is illuminated with monochromatic light of wavelength λ=6000A0 from a source 5 cm from its near edge. Find the fringe width on a screen 120 cm from the source . The perpendicular distance of the source from the mirror is 1 mm.

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a

36 cm

b

3.6 cm

c

0.36 cm

d

0.036 cm

answer is D.

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Detailed Solution

In a plane mirror, image is formed behind it as the object is in front of it. So, d = 2 mm = 0.2 cm, D = 120 cm , λ=6000A0=6000×10−8cm. Therefore, fringe width, β=λDd=6×10−5×1200.2=0.036 cm

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