A Lloyd’s mirror of length $$5$$ cm is illuminated with monochromatic light of wavelength λ$$=6000A0$$ from a source $$5$$ cm from its near edge. Find the fringe width on a screen $$120$$ cm from the source . The perpendicular distance of the source from the mirror is $$1$$ mm.

Question

A Lloyd’s mirror of length $$5$$ cm is illuminated with monochromatic light of wavelength λ$$=6000A0$$ from a source $$5$$ cm from its near edge. Find the fringe width on a screen $$120$$ cm from the source . The perpendicular distance of the source from the mirror is $$1$$ mm.

Infinity Learn · Accepted Answer

In a plane mirror, image is formed behind it as the object is in front of it.  So, d $$=$$ $$2$$ mm $$=$$ $$0.2$$ cm,   D $$=$$ $$120$$ cm , λ$$=6000A0=6000$$×$$10$$−$$8cm$$. Therefore, fringe width,  β$$=$$λ$$Dd=6$$×$$10$$−$$5$$×$$1200.2=0.036$$ cm

A Lloyd’s mirror of length 5 cm is illuminated with monochromatic light of wavelength $λ (= 6000 \overset{0}{A})$ from a source 5 cm from its near edge. Find the fringe width on a screen 120 cm from the source . The perpendicular distance of the source from the mirror is 1 mm.

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A Lloyd’s mirror of length 5 cm is illuminated with monochromatic light of wavelength λ=6000A0 from a source 5 cm from its near edge. Find the fringe width on a screen 120 cm from the source . The perpendicular distance of the source from the mirror is 1 mm.

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Ready to Test Your Skills?

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A Lloyd’s mirror of length 5 cm is illuminated with monochromatic light of wavelength $λ (= 6000 \overset{0}{A})$ from a source 5 cm from its near edge. Find the fringe width on a screen 120 cm from the source . The perpendicular distance of the source from the mirror is 1 mm.