Questions
ln the arrangement shown in figure the ends P and Q of an non-stretchable string move downwards with uniform speed U. Pulleys A and B are fixed. Mass M moves upwards with a speed
detailed solution
Correct option is D
As P and p fall down, the length / decreases at the rate of U m/s.From the figure, l2 = b2+v2Differentiating with respect to time2l × dldt = 2b×dbdt+2y×dydt(As dbdt=0, dldt = U)⇒ dydt = (ly)×dldt ⇒ dydt = (1cos θ)×U = Ucos θTalk to our academic expert!
Similar Questions
Two masses of I kg and 5 kg are attached to the ends of a massless string passing over a pulley of negligible weight. The pulley itself is attached to a light spring balance as shown in figure. The masses start moving during this interval; the reading of spring balance will be:
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