Questions
A load of 20 kg is suspended by a steel wire. Its frequency when rubbed with a resined cloth is found to be 20 times its frequency when plucked. If y of the wire is 19 .6 x 1o1r dyne/square cm, what is its area of cross-section ?
detailed solution
Correct option is C
When the wire is rubbed with resin cloth, its frequency is given byn1=12lYρ for a loaded wire n2=12lTaρ ∴ n1n2=YaT or 20=YaT or a=400TY=400×20×1000×98019⋅6×1011=4×10−3cm2Talk to our academic expert!
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