A load of 981 N is suspended from a steel wire of radius 1mm. The maximum angle through which the wire with a load can be deflected so that it does not break when the load passes through the position of equilibrium is computed as cos−1[α(0.081)]. Find α . (Breaking stress is 7.85×108N/m2 )
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.