Questions
A load suspended by a massless spring produces an extension of x cm in equilibrium. When it is cut into
two unequal parts, the same load produces an extension of 7.5 cm when suspended by the larger
part of length 60 cm. When it is suspended by the smaller part, the extension is 5.0 cm. Then,
detailed solution
Correct option is A
Elongation of the wire, Δl=FlAY (Can also be applied for a spring)∴ Δl∝l7.55.0=60l2⇒l2=40cm∴ Length of original spring is (60+ 40) cm= 100 cmNow, x7.5=10060x = 12.5cmTalk to our academic expert!
Similar Questions
Two similar springs P and Q have spring constants such that Kp > . They are stretched first by the same amount (case a), then by the same force (case b). The work done by the springs are related as, in case (a) and case (b), respectively.
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