On loading a metal wire of cross section $$10$$–$$6$$ $$m2$$ and length $$2$$ m by a mass of $$210$$ kg it extends by $$16$$ mm and suddenly broke from the point of support. If density of that metal is $$8000$$ kgm–$$3$$ and its specific heat is $$420$$ Jkg–$$1K$$–$$1$$, the rise in temperature of wire is (g$$ $$=$$ $$10$$ $$ms-2)

Question

Infinity Learn · Accepted Answer

Gravitational P.E. lost by the mass (M$$ $$=$$ $$210$$ $$kg) $$=$$ Mg.e $$50$$% of this lost energy is converted into heat. so . where m $$=$$ mass of wire.

On loading a metal wire of cross section 10^–6 m² and length 2 m by a mass of 210 kg it extends by 16 mm and suddenly broke from the point of support. If density of that metal is 8000 kgm^–3 and its specific heat is 420 Jkg^–1K^–1, the rise in temperature of wire is (g = 10 ms^-2)

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On loading a metal wire of cross section 10–6 m2 and length 2 m by a mass of 210 kg it extends by 16 mm and suddenly broke from the point of support. If density of that metal is 8000 kgm–3 and its specific heat is 420 Jkg–1K–1, the rise in temperature of wire is (g = 10 ms-2)

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On loading a metal wire of cross section 10^–6 m² and length 2 m by a mass of 210 kg it extends by 16 mm and suddenly broke from the point of support. If density of that metal is 8000 kgm^–3 and its specific heat is 420 Jkg^–1K^–1, the rise in temperature of wire is (g = 10 ms^-2)