The log-log graph between the energy E of an electron and its de-Broglie wavelength λ will be
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a
b
c
d
answer is C.
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Detailed Solution
λ=h2mE=h2m.1E.logλ=logh2m+log1E⇒logλ=logh2m−12logElogλ=−12logE+logh2mThis is the equation of straight line having slope −1/2 and positive intercept on logλ axis & logE axis