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Q.

The log-log graph between the energy E of an electron and its de-Broglie wavelength λ will be

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a

b

c

d

answer is C.

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Detailed Solution

λ=h2mE=h2m.1E.logλ=logh2m+log1E⇒logλ=logh2m−12logElogλ=−12logE+logh2mThis  is  the  equation  of  straight line  having slope  −1/2  and  positive  intercept   on  logλ  axis & logE axis
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