A long capillary tube of mass 'π' gm, radius 2 mm and negligible thickness, is partially immersed in a liquid of surface tension 0.1 N/m. Take angle of contact zero and neglect buoyant force of liquid. The force required to hold the tube vertically, will be (g = 10 m/s2)
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a
10.4 πmN
b
10.8 πmN
c
0.8 πmN
d
4.8 πmN
answer is B.
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Detailed Solution
The free body diagram of the capillary tube is as shown in the figure. Net force F required to hold tube isF = force due to surface tension at cross-section(S1+S2)+weight of tube. = (2πRT+2πRT)+mg = 4πRT+ mg