Q.

A long composite string is made up by joining two strings of different mass per unit length  μ  and 4μ respectively. The composite string is under the same tension. A transverse wave pulse Y=6 mmsin5t+40x, where ‘t’ is in seconds and ‘x’ is in metres, is sent along the lighter string towards the joint. The joint is at x=0 . The equation of the wave pulse reflected from the joint is

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a

Y=2 mmsin5t−40x

b

Y=4 mmsin40x−5t

c

Y=−2 mmsin5t−40x

d

Y=2 mmsin5t−10x

answer is C.

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Detailed Solution

Given wave pulse  Y=6 mmsin5t+40x......1We know speed of wave v=Tμ....2Assume  v1=Speed in string 1 (of density μ1 )v2=Speed in string 2 (of density  μ2)v1=Tμ;v2=T4μ⇒v1v2=2∴v2
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