Questions
A long conducting wire AH is moved over a conducting triangular wire CDE with a constant velocity v in a uniform magnetic field directed into the plane of the paper. Resistance per unit length of each wire is r. Then
detailed solution
Correct option is D
Magnetic flux in⊗ direction through the coil is increasing. Therefore, induced current will produce magnetic field in ⊙ direction. Thus, the current in the loop is anticlockwise. Magnitude of induced current at any instant of time is I=eR=Bv(FG)ρ(FG+GD+DF) When the wire AH moves downwards, FG,GD and DF all increase in the same ratio. Therefore, i is constant.Talk to our academic expert!
Similar Questions
The direction of induced current in the coils A and B in the coils A and B is the situation shown in the figure is
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