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Q.

A long conducting wire AH is moved over a conducting triangular wire CDE with a constant velocity v in a uniform magnetic field B→ directed into the plane of the paper. Resistance per unit length of each wire is ρ. Then

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a

a constant clockwise induced current will flow in the closed loop

b

an increasing anticlockwise induced current will flow in the closed loop

c

a decreasing anticlockwise induced current will flow in the closed loop

d

a constant anticlockwise induced current will flow in the closed loop

answer is D.

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Detailed Solution

As the wire AH slides, the enclosed area increases, so the magnetic flux in ⊗ direction through the coil is increasing. Therefore, induced current will produce magnetic field in ⊙ direction. Thus, the current in the loop is anticlockwise. Magnitude of induced current at any instant of time isi=eR=Bv(FG)ρ(FG+GD+DF)When the wire AH moves downwards FG, GD and DF all increase in the same ratio. Therefore, i is constant.
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A long conducting wire AH is moved over a conducting triangular wire CDE with a constant velocity v in a uniform magnetic field B→ directed into the plane of the paper. Resistance per unit length of each wire is ρ. Then