A long cylindrical wire of radius ‘a’ carries a current i distributed uniformly over its cross section. If the magnetic fields at distances ra from the axis have equal magnitude, then
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a
a=R+r2
b
a=Rr
c
a=Rr/R+r
d
a=R2/r
answer is B.
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Detailed Solution
Applying Ampere’s circular law. Inside point, B2πr=μ0Iπr2πa2 for raTaking the ratio rR=r2a2⇒a=Rr.