Q.

A long elastic spring is stretched by 2 cm and its potential energy is U. If the spring is stretched by 10 cm, the P.E., will be

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a

5 U

b

25 U

c

U/5

d

U/20

answer is B.

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Detailed Solution

The elastic potential is Energy =12 Stress × Strain =12Y( strain )2=12YΔlL2∴ U2U1∝Δl2Δl12=1022U2U1=25⇒U2=25U1=25U U1=U
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A long elastic spring is stretched by 2 cm and its potential energy is U. If the spring is stretched by 10 cm, the P.E., will be