A long elastic spring is stretched by 2 cm and its potential energy is U. If the spring is stretched by 10 cm, the P.E., will be

see full answer

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

5 U

25 U

U/5

U/20

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

The elastic potential is Energy =12 Stress × Strain =12Y( strain )2=12YΔlL2∴ U2U1∝Δl2Δl12=1022U2U1=25⇒U2=25U1=25U U1=U

Watch 3-min video & get full concept clarity