A long solenoid carrying a current produces a magnetic field B along its axis. If the current is doubled and the number of turns per cm is halved, the new value of the magnetic field is

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B/2

answer is A.

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Detailed Solution

B=μ0ni ⇒ BB' = nn' × ii' = 11/2 × 12 =1 ⇒ B'=B

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