First slide

Solenoid

Question

A long solenoid carrying a current produces a magnetic field B along its axis. If the current is doubled and the number of turns per cm is halved, the new value of the magnetic field is

Easy

A

B
B

2B
C

4B
D

B/2

Solution

$B = μ_{0} ni \Rightarrow \frac{B}{B^{'}} = \frac{n}{n^{'}} \times \frac{i}{i^{'}} = \frac{1}{(1 / 2)} \times \frac{1}{2} = 1 \Rightarrow B^{'} = B$

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