Questions
A long solenoid carrying a current produces a magnetic field B along its axis. If the current is doubled and the number of turns per cm is halved, the new value of the magnetic field is
detailed solution
Correct option is A
B=μ0ni ⇒ BB' = nn' × ii' = 11/2 × 12 =1 ⇒ B'=BTalk to our academic expert!
Similar Questions
A solenoid of 1 . 5 metre length and 4 .0 cm diameter possesses 10 turns per cm. A current of 5 ampere is flowing through it. The magnetic field at axis inside the solenoid is (Given: weber/amp metre)
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