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Q.

A long solenoid of diameter 0. 1 m has2×104 turns per metre. At the center of the solenoid, a 100-turn coil of radius 0.01 m is placed with its axis coinciding with the solenoid axis. The current in the solenoid is decreased at a constant rate from + 2 A to -2A in 0.05 s. Find the total charge  (in μC) flowing through the coil during this time when the resistance of the coil is 40π2Ω.

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answer is 8.

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Detailed Solution

The mutual inductance of solenoid coil systemM=μ0n1N2A2=μ0n1N2πr22=4π×10-7×2×104×100×π×0.012=8π2×10-5HEMF induced in the coil, e2=-M∆i∆t=-8π2×10-5×-2-20.05=640π2×10-5VRequired charge:q=i∆t=eR∆t=640×π2×10-540π2×0.05=8μC
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